18k^2-33k-50=0

Solution for 18k^2-33k-50=0 equation:

18k^2-33k-50=0

a = 18; b = -33; c = -50;
Δ = b2-4ac
Δ = -332-4·18·(-50)
Δ = 4689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4689}=\sqrt{9*521}=\sqrt{9}*\sqrt{521}=3\sqrt{521}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-3\sqrt{521}}{2*18}=\frac{33-3\sqrt{521}}{36}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+3\sqrt{521}}{2*18}=\frac{33+3\sqrt{521}}{36}
$